Foo also exports foo_bar(), which concatenates the output of foo() and bar(), and foo_blee(), which does the same with foo() and blee(). Bar has bar_foo() and bar_blee(), and Blee has blee_foo() and blee_bar().
Here, the library holding MyTools is identified using the PERL5LIB environment variable. I do this to model a problem shared by a suite of modules that have spaghetti-like tendencies to interconnect with each other. Previously, I had used
use lib '/path/to/lib'
to do this purpose, but the need to start using git and the like has pushed me toward using a means to identifying library paths without hardcoding them.I haven't developed the test case such that, using
use lib
, it works, but my production uses lib
all over the place, and I only noticed the problem when I copied it to a dev directory and pulled those lines.The problem I'm seeing is that Perl starts to look for foo() in Bar or Blee, when foo() is in Foo. Clearly, It'd be better if Foo didn't include Bar and Blee while Bar included Foo and Blee, etc. It would be nice if I had separated the code better in the first place, but seeing that the code base where I started finding this problem is 19 modules with over 8,000 lines and is used across several systems by someone else, so every change has the potential to break my lab's workflow, I can't really disentangle it right now.
So, it strikes me that Perl is wrong, too. (I fully admit that my code is an unruly hairball. I'm starting to pay that technical debt right now.) I'm somewhat loathe to tag this as an error in Perl and start filing bug reports until someone with more direct experience looks at this and says either "That's odd" or "Dave, you're a dumbass." I would certainly accept either answer.
So, am I wrong?